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Merging and Filtering Multiple Architect Contact Tables in the UK Using Clay

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I've created multiple tables looking for Architects in the UK, how do I merge all of these tables containing Architect contacts and use Clay to only find new contacts (So I don't use credits finding the same ones twice)? Many thanks in advance.

  • Avatar of Clay Team
    Clay Team
    APP
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    Hey hey! Can you drop the URL for your table here? (if applicable) 🫢 Don't worry, only admins will be able to open your table πŸ˜‰

  • Avatar of Nikhil B.
    Nikhil B.
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    curious about the finding only new people part, following

  • Avatar of Clay Team
    Clay Team
    APP
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    Hey there Adam sorry for the delay. Quick question for clarification are these tables are in CSV form?

  • Avatar of Adam R.
    Adam R.
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    The last table is a CSV of everything I've pulled from Linkedin so far (master)

  • Avatar of Clay Team
    Clay Team
    APP
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    Hey Adam! Happy to check it out... So, if you already have a master list you compiled into one Clay table after getting the CSVs, you could run additional searches and then cross-match against this bigger list with the Lookup Record integration to remove any duplicates/found matches before you enrich for more information.QQ, are you finding them on LI or where are you sourcing these people?

  • Avatar of Adam R.
    Adam R.
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    All from LinkedIn. How do I cross-ref in Clay and exclude from find work email recipe?

  • Avatar of Clay Team
    Clay Team
    APP
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    Currently, not possible to run a search and exclude existing lists of people but the team is working on that implementation soon. If you generate a new query and import another batch of contacts, the Lookup Record integration can help with that cross-match. Here's a video and our docs page for Lookup Record!

  • Avatar of Clay Team
    Clay Team
    APP
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    I'd suggest using the person's LI URL to find a match though, that way you can save credits and remove people before further enriching only the new ones.

  • Avatar of Adam R.
    Adam R.
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    Perfect, thanks Arturo O.